# Thảo luận:Nhập môn Giải tích/Tích phân/Tích phân bất định/Tích phân hàm lượng giác ngược

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==Arcsin

${\displaystyle \int \arcsin x\,dx=x\arcsin x+{\sqrt {1-x^{2}}}+C}$
${\displaystyle \int \arcsin {\frac {x}{a}}\ dx=x\arcsin {\frac {x}{a}}+{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x\arcsin {\frac {x}{a}}\ dx=\left({\frac {x^{2}}{2}}-{\frac {a^{2}}{4}}\right)\arcsin {\frac {x}{a}}+{\frac {x}{4}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{2}\arcsin {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\arcsin {\frac {x}{a}}+{\frac {x^{2}+2a^{2}}{9}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{n}\arcsin x\ dx={\frac {1}{n+1}}\left(x^{n+1}\arcsin x+{\frac {x^{n}{\sqrt {1-x^{2}}}-nx^{n-1}\arcsin x}{n-1}}+n\int x^{n-2}\arcsin x\ dx\right)}$

## Arccosine

${\displaystyle \int \arccos x\,dx=x\arccos x-{\sqrt {1-x^{2}}}+C}$
${\displaystyle \int \arccos {\frac {x}{a}}\ dx=x\arccos {\frac {x}{a}}-{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x\arccos {\frac {x}{a}}\ dx=\left({\frac {x^{2}}{2}}-{\frac {a^{2}}{4}}\right)\arccos {\frac {x}{a}}-{\frac {x}{4}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{2}\arccos {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\arccos {\frac {x}{a}}-{\frac {x^{2}+2a^{2}}{9}}{\sqrt {a^{2}-x^{2}}}+C}$

## Arctangent

${\displaystyle \int \arctan x\,dx=x\arctan x-{\frac {1}{2}}\ln(1+x^{2})+C}$
${\displaystyle \int \arctan {\big (}{\frac {x}{a}}{\big )}dx=x\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {a}{2}}\ln(1+{\frac {x^{2}}{a^{2}}})+C}$
${\displaystyle \int x\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {(a^{2}+x^{2})\arctan {\big (}{\frac {x}{a}}{\big )}-ax}{2}}+C}$
${\displaystyle \int x^{2}\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {x^{3}}{3}}\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {ax^{2}}{6}}+{\frac {a^{3}}{6}}\ln({a^{2}+x^{2}})+C}$
${\displaystyle \int x^{n}\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {x^{n+1}}{n+1}}\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {a}{n+1}}\int {\frac {x^{n+1}}{a^{2}+x^{2}}}\ dx,\quad n\neq -1}$

## Arccosecant

${\displaystyle \int \operatorname {arccsc} x\,dx=x\operatorname {arccsc} x+\ln \left|x+x{\sqrt {{x^{2}-1} \over x^{2}}}\right|+C}$
${\displaystyle \int \operatorname {arccsc} {\frac {x}{a}}\ dx=x\operatorname {arccsc} {\frac {x}{a}}+{a}\ln {({\frac {x}{a}}({\sqrt {1-{\frac {a^{2}}{x^{2}}}}}+1))}+C}$
${\displaystyle \int x\operatorname {arccsc} {\frac {x}{a}}\ dx={\frac {x^{2}}{2}}\operatorname {arccsc} {\frac {x}{a}}+{\frac {ax}{2}}{\sqrt {1-{\frac {a^{2}}{x^{2}}}}}+C}$

## Arcsecant

${\displaystyle \int \operatorname {arcsec} x\,dx=x\operatorname {arcsec} x-\ln \left|x+x{\sqrt {{x^{2}-1} \over x^{2}}}\right|+C}$
${\displaystyle \int \operatorname {arcsec} {\frac {x}{a}}\ dx=x\operatorname {arcsec} {\frac {x}{a}}+{\frac {x}{a|x|}}\ln \left|x\pm {\sqrt {x^{2}-1}}\right|+C}$
${\displaystyle \int x\operatorname {arcsec} x\ dx={\frac {1}{2}}\left(x^{2}\operatorname {arcsec} x-{\sqrt {x^{2}-1}}\right)+C}$
${\displaystyle \int x^{n}\operatorname {arcsec} x\ dx={\frac {1}{n+1}}\left(x^{n+1}\operatorname {arcsec} x-{\frac {1}{n}}\left[x^{n-1}{\sqrt {x^{2}-1}}+(1-n)\left(x^{n-1}\operatorname {arcsec} x+(1-n)\int x^{n-2}\operatorname {arcsec} x\ dx\right)\right]\right)}$

## Arccotangent

${\displaystyle \int \operatorname {arccot} x\,dx=x\operatorname {arccot} x+{\frac {1}{2}}\ln(1+x^{2})+C}$
${\displaystyle \int \operatorname {arccot} {\frac {x}{a}}\ dx=x\operatorname {arccot} {\frac {x}{a}}+{\frac {a}{2}}\ln(a^{2}+x^{2})+C}$
${\displaystyle \int x\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {a^{2}+x^{2}}{2}}\operatorname {arccot} {\frac {x}{a}}+{\frac {ax}{2}}+C}$
${\displaystyle \int x^{2}\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\operatorname {arccot} {\frac {x}{a}}+{\frac {ax^{2}}{6}}-{\frac {a^{3}}{6}}\ln(a^{2}+x^{2})+C}$
${\displaystyle \int x^{n}\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {x^{n+1}}{n+1}}\operatorname {arccot} {\frac {x}{a}}+{\frac {a}{n+1}}\int {\frac {x^{n+1}}{a^{2}+x^{2}}}\ dx,\quad n\neq -1}$

## Arcsine

${\displaystyle \int \arcsin x\,dx=x\arcsin x+{\sqrt {1-x^{2}}}+C}$
${\displaystyle \int \arcsin {\frac {x}{a}}\ dx=x\arcsin {\frac {x}{a}}+{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x\arcsin {\frac {x}{a}}\ dx=\left({\frac {x^{2}}{2}}-{\frac {a^{2}}{4}}\right)\arcsin {\frac {x}{a}}+{\frac {x}{4}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{2}\arcsin {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\arcsin {\frac {x}{a}}+{\frac {x^{2}+2a^{2}}{9}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{n}\arcsin x\ dx={\frac {1}{n+1}}\left(x^{n+1}\arcsin x+{\frac {x^{n}{\sqrt {1-x^{2}}}-nx^{n-1}\arcsin x}{n-1}}+n\int x^{n-2}\arcsin x\ dx\right)}$

## Arccosine

${\displaystyle \int \arccos x\,dx=x\arccos x-{\sqrt {1-x^{2}}}+C}$
${\displaystyle \int \arccos {\frac {x}{a}}\ dx=x\arccos {\frac {x}{a}}-{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x\arccos {\frac {x}{a}}\ dx=\left({\frac {x^{2}}{2}}-{\frac {a^{2}}{4}}\right)\arccos {\frac {x}{a}}-{\frac {x}{4}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{2}\arccos {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\arccos {\frac {x}{a}}-{\frac {x^{2}+2a^{2}}{9}}{\sqrt {a^{2}-x^{2}}}+C}$

## Arctangent

${\displaystyle \int \arctan x\,dx=x\arctan x-{\frac {1}{2}}\ln(1+x^{2})+C}$
${\displaystyle \int \arctan {\big (}{\frac {x}{a}}{\big )}dx=x\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {a}{2}}\ln(1+{\frac {x^{2}}{a^{2}}})+C}$
${\displaystyle \int x\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {(a^{2}+x^{2})\arctan {\big (}{\frac {x}{a}}{\big )}-ax}{2}}+C}$
${\displaystyle \int x^{2}\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {x^{3}}{3}}\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {ax^{2}}{6}}+{\frac {a^{3}}{6}}\ln({a^{2}+x^{2}})+C}$
${\displaystyle \int x^{n}\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {x^{n+1}}{n+1}}\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {a}{n+1}}\int {\frac {x^{n+1}}{a^{2}+x^{2}}}\ dx,\quad n\neq -1}$

## Arccosecant

${\displaystyle \int \operatorname {arccsc} x\,dx=x\operatorname {arccsc} x+\ln \left|x+x{\sqrt {{x^{2}-1} \over x^{2}}}\right|+C}$
${\displaystyle \int \operatorname {arccsc} {\frac {x}{a}}\ dx=x\operatorname {arccsc} {\frac {x}{a}}+{a}\ln {({\frac {x}{a}}({\sqrt {1-{\frac {a^{2}}{x^{2}}}}}+1))}+C}$
${\displaystyle \int x\operatorname {arccsc} {\frac {x}{a}}\ dx={\frac {x^{2}}{2}}\operatorname {arccsc} {\frac {x}{a}}+{\frac {ax}{2}}{\sqrt {1-{\frac {a^{2}}{x^{2}}}}}+C}$

## Arcsecant

${\displaystyle \int \operatorname {arcsec} x\,dx=x\operatorname {arcsec} x-\ln \left|x+x{\sqrt {{x^{2}-1} \over x^{2}}}\right|+C}$
${\displaystyle \int \operatorname {arcsec} {\frac {x}{a}}\ dx=x\operatorname {arcsec} {\frac {x}{a}}+{\frac {x}{a|x|}}\ln \left|x\pm {\sqrt {x^{2}-1}}\right|+C}$
${\displaystyle \int x\operatorname {arcsec} x\ dx={\frac {1}{2}}\left(x^{2}\operatorname {arcsec} x-{\sqrt {x^{2}-1}}\right)+C}$
${\displaystyle \int x^{n}\operatorname {arcsec} x\ dx={\frac {1}{n+1}}\left(x^{n+1}\operatorname {arcsec} x-{\frac {1}{n}}\left[x^{n-1}{\sqrt {x^{2}-1}}+(1-n)\left(x^{n-1}\operatorname {arcsec} x+(1-n)\int x^{n-2}\operatorname {arcsec} x\ dx\right)\right]\right)}$

## Arccotangent

${\displaystyle \int \operatorname {arccot} x\,dx=x\operatorname {arccot} x+{\frac {1}{2}}\ln(1+x^{2})+C}$
${\displaystyle \int \operatorname {arccot} {\frac {x}{a}}\ dx=x\operatorname {arccot} {\frac {x}{a}}+{\frac {a}{2}}\ln(a^{2}+x^{2})+C}$
${\displaystyle \int x\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {a^{2}+x^{2}}{2}}\operatorname {arccot} {\frac {x}{a}}+{\frac {ax}{2}}+C}$
${\displaystyle \int x^{2}\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\operatorname {arccot} {\frac {x}{a}}+{\frac {ax^{2}}{6}}-{\frac {a^{3}}{6}}\ln(a^{2}+x^{2})+C}$
${\displaystyle \int x^{n}\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {x^{n+1}}{n+1}}\operatorname {arccot} {\frac {x}{a}}+{\frac {a}{n+1}}\int {\frac {x^{n+1}}{a^{2}+x^{2}}}\ dx,\quad n\neq -1}$

The following is a list of integrals (antiderivative formulas) for integrands that contain inverse trigonometric functions (also known as "arc functions"). For a complete list of integral formulas, see lists of integrals.

C is used for the arbitrary constant of integration that can only be determined if something about the value of the integral at some point is known. Thus each function has an infinite number of antiderivatives.

Note: There are three common notations for inverse trigonometric functions. The arcsine function, for instance, could be written as sin−1, asin, or, as is used on this page, arcsin.

## Arcsine

${\displaystyle \int \arcsin x\,dx=x\arcsin x+{\sqrt {1-x^{2}}}+C}$
${\displaystyle \int \arcsin {\frac {x}{a}}\ dx=x\arcsin {\frac {x}{a}}+{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x\arcsin {\frac {x}{a}}\ dx=\left({\frac {x^{2}}{2}}-{\frac {a^{2}}{4}}\right)\arcsin {\frac {x}{a}}+{\frac {x}{4}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{2}\arcsin {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\arcsin {\frac {x}{a}}+{\frac {x^{2}+2a^{2}}{9}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{n}\arcsin x\ dx={\frac {1}{n+1}}\left(x^{n+1}\arcsin x+{\frac {x^{n}{\sqrt {1-x^{2}}}-nx^{n-1}\arcsin x}{n-1}}+n\int x^{n-2}\arcsin x\ dx\right)}$

## Arccosine

${\displaystyle \int \arccos x\,dx=x\arccos x-{\sqrt {1-x^{2}}}+C}$
${\displaystyle \int \arccos {\frac {x}{a}}\ dx=x\arccos {\frac {x}{a}}-{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x\arccos {\frac {x}{a}}\ dx=\left({\frac {x^{2}}{2}}-{\frac {a^{2}}{4}}\right)\arccos {\frac {x}{a}}-{\frac {x}{4}}{\sqrt {a^{2}-x^{2}}}+C}$
${\displaystyle \int x^{2}\arccos {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\arccos {\frac {x}{a}}-{\frac {x^{2}+2a^{2}}{9}}{\sqrt {a^{2}-x^{2}}}+C}$

## Arctangent

${\displaystyle \int \arctan x\,dx=x\arctan x-{\frac {1}{2}}\ln(1+x^{2})+C}$
${\displaystyle \int \arctan {\big (}{\frac {x}{a}}{\big )}dx=x\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {a}{2}}\ln(1+{\frac {x^{2}}{a^{2}}})+C}$
${\displaystyle \int x\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {(a^{2}+x^{2})\arctan {\big (}{\frac {x}{a}}{\big )}-ax}{2}}+C}$
${\displaystyle \int x^{2}\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {x^{3}}{3}}\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {ax^{2}}{6}}+{\frac {a^{3}}{6}}\ln({a^{2}+x^{2}})+C}$
${\displaystyle \int x^{n}\arctan {\big (}{\frac {x}{a}}{\big )}dx={\frac {x^{n+1}}{n+1}}\arctan {\big (}{\frac {x}{a}}{\big )}-{\frac {a}{n+1}}\int {\frac {x^{n+1}}{a^{2}+x^{2}}}\ dx,\quad n\neq -1}$

## Arccosecant

${\displaystyle \int \operatorname {arccsc} x\,dx=x\operatorname {arccsc} x+\ln \left|x+x{\sqrt {{x^{2}-1} \over x^{2}}}\right|+C}$
${\displaystyle \int \operatorname {arccsc} {\frac {x}{a}}\ dx=x\operatorname {arccsc} {\frac {x}{a}}+{a}\ln {({\frac {x}{a}}({\sqrt {1-{\frac {a^{2}}{x^{2}}}}}+1))}+C}$
${\displaystyle \int x\operatorname {arccsc} {\frac {x}{a}}\ dx={\frac {x^{2}}{2}}\operatorname {arccsc} {\frac {x}{a}}+{\frac {ax}{2}}{\sqrt {1-{\frac {a^{2}}{x^{2}}}}}+C}$

## Arcsecant

${\displaystyle \int \operatorname {arcsec} x\,dx=x\operatorname {arcsec} x-\ln \left|x+x{\sqrt {{x^{2}-1} \over x^{2}}}\right|+C}$
${\displaystyle \int \operatorname {arcsec} {\frac {x}{a}}\ dx=x\operatorname {arcsec} {\frac {x}{a}}+{\frac {x}{a|x|}}\ln \left|x\pm {\sqrt {x^{2}-1}}\right|+C}$
${\displaystyle \int x\operatorname {arcsec} x\ dx={\frac {1}{2}}\left(x^{2}\operatorname {arcsec} x-{\sqrt {x^{2}-1}}\right)+C}$
${\displaystyle \int x^{n}\operatorname {arcsec} x\ dx={\frac {1}{n+1}}\left(x^{n+1}\operatorname {arcsec} x-{\frac {1}{n}}\left[x^{n-1}{\sqrt {x^{2}-1}}+(1-n)\left(x^{n-1}\operatorname {arcsec} x+(1-n)\int x^{n-2}\operatorname {arcsec} x\ dx\right)\right]\right)}$

## Arccotangent

${\displaystyle \int \operatorname {arccot} x\,dx=x\operatorname {arccot} x+{\frac {1}{2}}\ln(1+x^{2})+C}$
${\displaystyle \int \operatorname {arccot} {\frac {x}{a}}\ dx=x\operatorname {arccot} {\frac {x}{a}}+{\frac {a}{2}}\ln(a^{2}+x^{2})+C}$
${\displaystyle \int x\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {a^{2}+x^{2}}{2}}\operatorname {arccot} {\frac {x}{a}}+{\frac {ax}{2}}+C}$
${\displaystyle \int x^{2}\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {x^{3}}{3}}\operatorname {arccot} {\frac {x}{a}}+{\frac {ax^{2}}{6}}-{\frac {a^{3}}{6}}\ln(a^{2}+x^{2})+C}$
${\displaystyle \int x^{n}\operatorname {arccot} {\frac {x}{a}}\ dx={\frac {x^{n+1}}{n+1}}\operatorname {arccot} {\frac {x}{a}}+{\frac {a}{n+1}}\int {\frac {x^{n+1}}{a^{2}+x^{2}}}\ dx,\quad n\neq -1}$